Mathématiques

Question

A=x²-4+(x-2)(2x+1)
B=2x-3+(3-2x)²
C=(2a+1)²-(a+6)²
D=(2x-3)(1-x)-3(x-1)(x+2)

Développe et factorise chaque expression.

s'il vous plait j'ai besoin d aide pour mon DM.

1 Réponse

  • A=x²-4+(x-2)(2x+1)
    a = x²-4 +2x²+x-4x-2
    a = 3x²-3x-5

    B=2x-3+(3-2x)²
    b = 2x-3 +9-12x+4x²
    b = 4x²-10x+6

    C=(2a+1)²-(a+6)²
    c =4a²+4a+1 -(a²+12a+36)
    c = 4a²+4a+1-a²-12a-36
    c = 3a² -8a-35

    D=(2x-3)(1-x)-3(x-1)(x+2)
    d = 2x-2x²-3+3x -3(x²+2x-x-2)
    d = -2x²+5x-3 -3x² -6x+3x+6
    d = -5x² +2x+3

    factoriser
    A=x²-4+(x-2)(2x+1)
    a = (x-2)(x+2) +(x-2)(2x+1)
    a =(x-2)(x+2+2x+1)
    a =(x-2)(3x+3)
    a =3(x-2)(x+1)

    B=2x-3+(3-2x)²
    b =(-3+2x) +(3-2x)²
    b = -(3-2x) +(3-2x)²
    b =(3-2x)(-1+3-2x)
    b =(3-2x) (-2x+2)
    b =2(3-2x)(-x+1)

    C=(2a+1)²-(a+6)²
    c =(2a+1-a-6)(2a+1+a+6)
    c=(a-5)(3a+7)

    D=(2x-3)(1-x)-3(x-1)(x+2)
    d = -(-2x+3)(x-1) -3(x-1)(x+2)
    d =(x-1)(+2x-3 -3x-6)
    d =(x-1)(-x-9)

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