Développe et réduis les expressions suivantes : D = ( x – 2 ) ( x + 2 ) – 4x ( x – 6 ) E = 4 ( 5x + 2 ) ( 3 – x ) – ( x + 2 ) ( 2x – 1 ) V = ( x + 1 )2 + ( x –

D = ( x – 2 ) ( x + 2 ) – 4x ( x – 6 )
d = x²+2x-2x-4 -4x²+24x
d =  -3x²+24x-4


E= 4 ( 5x + 2 ) ( 3 – x ) – ( x + 2 ) ( 2x – 1 )
e = 4(15x-5x²+6-2x) -(2x²-x+4x-2)
e =60x -20x² +24 -8x -2x²+x-4x+2
e =  -22x² +49x +26


V = ( x + 1 )² + ( x – 1 )²
v = x²+2x+1 +x²-2x+1
v = 2x²+2

D= (x-2)(x+2)-4x(x-6) =

x²+2x-x-2x- (4x²-24x)=
x²-x-4x²+24x=
3x²+23x

E= 4(5x+2)(3-x)-(x+2)(2x-1)=

4(15x-5x²+6-2x)-(2x²-x+4x-2)=
60x-20x²+24-8x-2x²+x-4x+2=
49x-22x²+24

V=(x+1) ²+(x-1)²=
x²-1